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Re: [Discuss-gnuradio] USRP output power
From: |
Marcus D. Leech |
Subject: |
Re: [Discuss-gnuradio] USRP output power |
Date: |
Mon, 25 Apr 2011 12:13:34 -0400 |
User-agent: |
Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.15) Gecko/20110303 Thunderbird/3.1.9 |
On 25/04/2011 11:42 AM, Nick Foster wrote:
The USRP does not have a calibrated output or input and you will have to
calibrate it using a measuring receiver, calibrated signal generator, or
power meter in order to obtain meaningful results.
--n
I don't think precise values are really required here. The typical
Eb/N0 estimates are just that, *estimates*.
Let's assume that those bits leave the transmitter at "full-power"
(+20dBm), and radiate isotropically through free-space,
until they get to the receiver. At the receiver, the signal is
received against a locally-generated noise-background of some
magnitude. I think the noise figure of the RFX2400 is in the
neighbourhood of 5-6dB at maximum gain. A noise figure of 3dB
is equivalent to a noise power of -174dBm/Hz of bandwidth, so let's
call the noise power at the receiver -170dBm/Hz to
make the math easier.
Now, what is the equivalent bandwidth of each bit? Let's say it's 10KHz
for argument's sake. That means that the receiver
noise power over the bandwidth of a bit is -170dBm/Hz + 40dBHz =
-130dBm of noise power at the receiver over the bandwidth
occupied by our theoretical 10KHz bit.
The signal itself leaves the transmitter, and suffers free-space path
loss in a roughly inverse-cube law. Over a 1M path, that
signal suffers (assuming a perfectly-isotropic transmit antenna at
2.4GHz) a path loss of about 40dB, which brings the received signal
down to about -20dBm. So that -20dBm is set "against" a receiver
noise over the same bandwidth of -130dBm. The calculation of
the linear-units EB/N0 is left as an exercise for the reader.