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bug#66117: 30.0.50; `find-buffer-visiting' is slow when opening large nu


From: Gerd Möllmann
Subject: bug#66117: 30.0.50; `find-buffer-visiting' is slow when opening large number of buffers
Date: Tue, 02 Jan 2024 12:08:09 +0100
User-agent: Gnus/5.13 (Gnus v5.13)

Ihor Radchenko <yantar92@posteo.net> writes:

> Gerd Möllmann <gerd.moellmann@gmail.com> writes:
>
>>>>>> C-h f default-value explains this:
>>>>>>
>>>>>>   Return SYMBOL’s default value.
>>>>>>   This is the value that is seen in buffers that do not have their own 
>>>>>> values
>>>>>>   for this variable.
>>>>>
>>> ...
>>> I am sorry, but I do not see how the docstring explains what is
>>> happening there. Because it is not clear what `let' does with the
>>> default value.
>>
>> Sorry for not being clear. What I wanted to hint at is the part of the
>> doc string that reads "that do not have their own values...", which
>> means that what default-value returns depends whether or not SYMBOL got
>> its own value in the buffer, and that depends on the presence of lets,
>> and so on.
>
> It is not how I read this. AFAIU, `default-value' returns the value that
> is used for buffers where the value is not explicitly set. Calling
> `default-value' from inside the buffer where the value is set does not
> change that global default value and should not change what
> `default-value' returns.
>
> And indeed
>
> (defvar-local yant/test 'default-value)
> (with-temp-buffer
>   (setq yant/test 'local-value)
>   (default-value 'yant/test)) ; => 'default-value

Maybe the documentation could be changed to be clearer, but I'm afraid I
don't know how, because I think it describes 100% what is happening: the
setq creates a buffer-local binding in the temp buffer, and
default-value returns the value that is used in the case that a buffer
does _not_ have its own value, which is the value set in the
defvar-local...





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